Skip to main content

Java Exception Handling MCQ Test

  Loading…

Reading character arrays and integer arrays in Java

To read character arrays and integer arrays in Java, you can use the `Scanner` class or the `BufferedReader` class. Here's how to do it using each approach:

1. Using Scanner class:

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {

        Scanner scanner = new Scanner(System.in);


        // Reading a character array

        System.out.print("Enter a string: ");

        String str = scanner.nextLine();

        char[] charArray = str.toCharArray();


        // Reading an integer array

        System.out.print("Enter the size of the integer array: ");

        int size = scanner.nextInt();

        int[] intArray = new int[size];

        System.out.println("Enter " + size + " integers separated by spaces:");

        for (int i = 0; i < size; i++) {

            intArray[i] = scanner.nextInt();

        }


        // Displaying the character array

        System.out.print("Character array: ");

        for (char ch : charArray) {

            System.out.print(ch + " ");

        }

        System.out.println();


        // Displaying the integer array

        System.out.print("Integer array: ");

        for (int num : intArray) {

            System.out.print(num + " ");

        }


        scanner.close();

    }

}



2. Using BufferedReader class:

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;


public class Main {

    public static void main(String[] args) {

        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));


        try {

            // Reading a character array

            System.out.print("Enter a string: ");

            String str = reader.readLine();

            char[] charArray = str.toCharArray();


            // Reading an integer array

            System.out.print("Enter the size of the integer array: ");

            int size = Integer.parseInt(reader.readLine());

            int[] intArray = new int[size];

            System.out.println("Enter " + size + " integers separated by spaces:");

            String[] tokens = reader.readLine().split(" ");

            for (int i = 0; i < size; i++) {

                intArray[i] = Integer.parseInt(tokens[i]);

            }


            // Displaying the character array

            System.out.print("Character array: ");

            for (char ch : charArray) {

                System.out.print(ch + " ");

            }

            System.out.println();


            // Displaying the integer array

            System.out.print("Integer array: ");

            for (int num : intArray) {

                System.out.print(num + " ");

            }


            reader.close();

        } catch (IOException e) {

            System.out.println("Error reading input: " + e.getMessage());

        }

    }

}

Both approaches allow you to read character arrays and integer arrays from the standard input and display them to the user. The Scanner class provides a simpler and more convenient way to read input, while the BufferedReader class offers more flexibility and control over input handling.

Comments

Popular posts from this blog

Passing and Returning Objects in Java Methods

Passing and Returning Objects in Java Methods In Java, objects can be passed as parameters to methods and returned from methods just like other primitive data types. This allows for flexibility and the manipulation of object state within methods. Let's explore how passing and returning objects work in Java. Passing Objects as Parameters When you pass an object as a parameter to a method, you are essentially passing a reference to that object. This means that changes made to the object inside the method will affect the original object outside the method.  Example: class Car {     String model;     Car(String model) {         this.model = model;     } } public class CarProcessor {     // Method to modify the Car object     static void modifyCar(Car car, String newModel) {         car.model = newModel;     }     public static void main(String[] args) {       ...

Why is String[] args necessary in main() method in Java?

  Why is String[] args necessary in main() method in Java? In Java, the main method serves as the entry point for the program. The correct syntax for the main method is: public static void main (String[] args) { System.out.println( "Hello, Java!" ); } 🔹 Breaking it down: public → Accessible from anywhere. static → No need to create an object of the class to run it. void → No return value. main → Special method recognized by the JVM as the starting point. String[] args → Stores command-line arguments (optional but required by JVM). Why Can't We Skip String[] args ? JVM looks for main(String[] args) When you run a Java program, the JVM searches for the main method with exactly this signature : public static void main (String[] args) If you change or remove String[] args , the JVM cannot find the correct main() method and throws a runtime error (NoSuchMethodError). Java Specification Requires It The Java Language Specification (JLS) defines that main...